365体育足球滚球比分I am attempting to make a simple client and server in Python. The server seems to be completely fine but the client throws the following error:
File "C:\Users\me\Desktop\Client.py", line 6, in <module> connection, address = client.accept() File "C:\Users\me\AppData\Local\Programs\Python\Python38-32\lib\socket.py", line 292, in accept fd, addr = self._accept() OSError: [WinError 10022] An invalid argument was supplied
Here is the server code:
server = socket.socket(socket.AF_INET, socket.SOCK_STREAM) server.bind((socket.gethostname(), 8080)) server.listen(5) while True: connection, address = server.accept() fromClient = '' while True: data = connection.recv(2048) if not data: break fromClient = fromClient + data print(fromClient) connection.send(str.encode('yo')) connection.close() print('client disconnected')
365体育足球滚球比分Here is the client code:
import time client = socket.socket(socket.AF_INET, socket.SOCK_STREAM) client.connect((socket.gethostname(), 8080)) client.settimeout(3) time.sleep(3) #client.send(str.encode('client')) connection, address = client.accept() fromServer = client.recv(2048) fromServer = fromServer.decode('utf-8') client.close() print(fromServer)
The server binds to the ip and port so they are OK, but the client errors out when attempting the same thing. Is there anything I can do to fix this problem?
I have also tried sleeping before the client.accept() line and this has not worked.